
- Electrical Machines - Home
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- DC Machines
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- Types of Armature Winding in DC Machines
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- Induction Motors
- Introduction to Induction Motor
- Single-Phase Induction Motor
- 3-Phase Induction Motor
- Construction of 3-Phase Induction Motor
- 3-Phase Induction Motor on Load
- Characteristics of 3-Phase Induction Motor
- Speed Regulation and Speed Control
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- 3-Phase Induction Motor Fault Types
- Synchronous Machines
- Introduction to 3-Phase Synchronous Machines
- Construction of Synchronous Machine
- Working of 3-Phase Alternator
- Armature Reaction in Synchronous Machines
- Output Power of 3-Phase Alternator
- Losses and Efficiency of an Alternator
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- AC Motor Types
- Induction Generator (Asynchronous Generator)
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- Stationary Armature vs Rotating Field Alternator Advantages
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- Significance of Short Circuit Ratio in Alternator
- Hunting Effect Alternator
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- Excitation System of Synchronous Machine
- Equivalent Circuit Phasor Diagram of Synchronous Generator
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- Constant Flux Linkage Theorem
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- Salient Pole Synchronous Machine Theory
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- Types of Faults in Alternator
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- Electrical Generator
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- Solid State Motor Starters
- Characteristics of Single-Phase Motor
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- Three-Point Starter
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Electrical Machines - Direct On Line (DOL) Starter
Wiring Diagram and Working Principle of DOL Starter
The connection diagram of the Direct On Line (DOL) starter is shown in the figure. In the DOL method of starting a squirrel cage induction motor, the motor is connected to the full supply voltage through a starter.

The direct-on line starter consists of a coil operated contactor C which is controlled by start (normally open) push button and stop (normally closed) push button.
When the start push button (S1) is pressed, the contactor coil C is energies from two line conductors R and Y. The three main contacts (M) and the auxiliary contact (A) close and the terminals x and y are short circuited. Hence, the induction motor is connected to the supply voltage.
When the start push button is released, it moves back under the control of spring. Even then the contactor coil C remains energised through the terminals x and y. Thus, the main contacts (M) remain closed and the motor continues to get the supply voltage. Consequently, the auxiliary contact (A) is also known as hold-on-contact.
When the stop push button (S2) is pressed, the supply through the contactor coil C is disconnected, thus, the contactor coil C is de-energised. As a result of it, the main contacts (M) and the auxiliary contact (A) are opened. The supply to the motor is disconnected and hence the motor stops.
Overload Protection
When an overload occurs on the motor, the overload relays are energised. The normally closed contact (D) is opened and the contactor coil C is de-energised to disconnect the motor from the supply.
The fuses are connected in the circuit to provide the short-circuit protection to the motor.
Under-Voltage Protection
When the voltage across the motor terminals drops below a certain value or the supply failure occur during the operation of the motor, then the contactor coil C is de-energised. Thus, the motor is disconnected from the supply.
The direct-on line starter is a simple and less expensive starter for starting the squirrel cage induction motors. For this starter, the starting current drawn by the motor may be as large as 10 times of the full-load current of the motor and the starting torque is equal to the rated torque. Hence, this large starting current produces excessive voltage drop in the supply system to which the motor is connected. Therefore, the small motors up to 5 kW rating may be started by direct on line starters to avoid the fluctuations in the supply voltage.
Theory of Direct-On Line Starter
Let,
- Ist = Starting Current of the Motor per Phase
- Ifl = Full Load Current of the Motor per Phase
- τst = Starting Torque of the Motor
- τfl = Full Load Torque of the Motor
- sfl = Slip Corresponding to Full Load
Now, the rotor copper losses are given by,
$$\mathrm{\text{Rotor copper loss } \: = \: s \: \times \: rotor \: input}$$
$$\mathrm{\Rightarrow \: 3 \: I_{2}^{2} R_{2} \: = \: s \: \times \: 2\pi n_{s}\tau}$$
Therefore, the electromagnetic torque is,
$$\mathrm{\tau \: = \: \frac{3 I_{2}^{2} R_{2} }{2\pi n_{s} \tau} \:\: \dotso \: (1)}$$
here, ns is the synchronous speed in r.p.s.
At starting of the motor, s = 1; I2 = I2st; τ = τst, then,
$$\mathrm{\text{Starting torque, } \: \tau_{st} \: = \: \frac{3I_{2st}^{2} R_2}{2\pi n_{s}} \:\: \dotso \: (2)}$$
At full-load, s = sfl; I2 = I2fl; τ = τfl, then,
$$\mathrm{\text{Full - load torque, } \: \tau_{fl} \: = \: \frac{3I_{2fl}^{2} R_2}{2\pi n_{s}s_{fl}} \:\: \dotso \: (3)}$$
Hence, the ratio of starting torque to the full-load torque will be,
$$\mathrm{\frac{\tau_{st}}{\tau_{fl}} \:=\: \frac{\left(\frac{3I_{2st}^{2} R_2}{2\pi n_{s}}\right)}{\left(\frac{3I_{2fl}^{2} R_{2}}{2\pi n_{s}s_{fl}}\right)}}$$
$$\mathrm{\Rightarrow \: \frac{\tau_{st}}{\tau_{fl}} \: = \: \left(\frac{I_{2st}}{I_{2fl}}\right)^{2} \: \times \:s_{fl} \:\: \dotso \: (4)}$$
If the no-load current of the motor is neglected, then,
$$\mathrm{\frac{\text{Effective stator turns}}{\text{Effective rotor turns}} \: = \: \frac{I_{2st}}{I_{st}}}$$
Also,
$$\mathrm{\frac{\text{Effective stator turns}}{\text{Effective rotor turns}} \:=\: \frac{I_{2fl}}{I_{fl}}}$$
$$\mathrm{\therefore \: \frac{I_{2fl}}{I_{fl}} \: = \: \frac{I_{2st}}{I_{st}}}$$
$$\mathrm{\Rightarrow \: \frac{I_{st}}{I_{fl}} \: = \: \frac{I_{2st}}{I_{2fl}} \:\: \dotso \: (5)}$$
From eqns. (4) and (5), we get,
$$\mathrm{\frac{\tau_{st}}{\tau_{fl}} \:=\: \left(\frac{I_{st}}{I_{fl}}\right)^{2} \: \times \: s_{fl} \:\: \dotso \: (6)}$$
Now, if V1 is the stator voltage per phase equivalent and Ze10 is the per phase impedance of the motor referred to stator at standstill, then the starting current is,
$$\mathrm{I_{st} \: = \: \frac{V_1}{Z_{e10}} \:=\: I_{sc} \:\: \dotso \: (7)}$$
Hence, the starting current is equal to the short circuit current of the motor. From eqns. (6) and (7), we have,
$$\mathrm{\frac{\tau_{st}}{\tau_{fl}} \:=\: \left(\frac{I_{sc}}{I_{fl}}\right)^{2} \: \times \: s_{fl} \:\: \dotso \:(8)}$$