Induction Motor - Construction of Circle Diagram



Circle Diagram of Induction Motor

The circle diagram is a graphical representation of the performances of an induction motor. It is very useful to study the performance of an induction motor under all operating conditions. The construction of the circle diagram of an induction motor is based on the equivalent circuit of the motor which is shown in Figure-1.

Circle Diagram of Induction Motor1

By applying KCL in the equivalent circuit, we can write,

$$\mathrm{I_{1} \: = \: I_{0} \:+\: I'_2 \:\: \dotso \: (1)}$$

Circle Diagram of Induction Motor2

If the phase voltage V1 is taken along the vertical axis of OY as shown in Figure-2. Then, the no-load current (I0) lags behind the voltage V1 by an angle 0. Where, 0 is the no-load power factor angle and is of the order of 60°-80° because to produce the required flux per pole in the air gap of the machine, a large magnetising current is needed.

Now, at no-load, the slip s = 0, then

$$\mathrm{\frac{R_2}{s} \: = \: \infty \: i.e. \: \text{ open circuited at no - load }}$$

$$\mathrm{\therefore I_{0} \: = \: \frac{V_{1}}{Z_{NL}} \:\: \dotso \: (2)}$$

Where,

$$\mathrm{Z_{NL} \:=\: (R_{0} \: || \: jX_0) \: = \: \text{ No load impedance}}$$

Here, all the rotational losses are taken into account by R0. Then, the no-load losses are given by,>

$$\mathrm{P_{0} \: =\: V_{1}I_{0} \: \cos \varphi_{0}\:\: \dotso \: (3)}$$

The rotor current referred to the stator side is given by,

$$\mathrm{I'_{2}\: =\: \frac{V_{1}}{Z'_{e1}}\:=\:\frac{V_{1}}{\sqrt{\left(R_{1} \:+\: \frac{R'_{2}}{s}\right)^{2}\:+\: (X_{1} \: +\: X'_{2})^{2}}}\:\: \dotso \: (4)}$$

This rotor current I'2 lags behind the voltage V1 by the impedance angle .

Refer Figure-3,

Circle Diagram of Induction Motor3

$$\mathrm{\sin\:\varphi\: =\: \frac{X_{1} \:+\: X'_{2}}{\sqrt{\left(R_{1} \:+\: \frac{R'_{2}}{s}\right)^{2}\:+\: (X_{1} \:+\: X'_{2})^{2}}}\:\: \dotso \: (5)}$$

Hence, by combining the eqns. (4) & (5), we get,

$$\mathrm{I'_{2} \:=\: \frac{V_{1}}{X_{1} \:+\: X'_{2}}\: \sin \varphi \:\: \dotso \: (6)}$$

Eqn. (6) is in the form of r = a sin θ, which represents a circle with diameter a. Therefore, the locus of current (I'2) is a circle whose diameter is

$$\mathrm{diameter \: = \: \frac{V_{1}}{X_{1} \:+\: X'_{2}}}$$

It is shown in Figure-4.

Circle Diagram of Induction Motor4

The radius of the circle is,

$$\mathrm{O'C \:=\: \frac{V_{1}}{2(X_{1} \:+\: X'_{2})}}$$

From eqn. (1), it is clear that the stator current I1 is found by combining the results shown in Figures-2, 3, and 4. Then, the resulting figure obtained is shown in Figure-5 which is known as the circle diagram of the induction motor.

Circle Diagram of Induction Motor5

Construction of Circle Diagram of Induction Motor

The data required to draw the circle diagram of an induction motor are −

  • Stator phase voltage,

$$\mathrm{V_1 =\frac{V_}{\sqrt{3}}}$$

  • No-load current (I0) of the motor
  • No-load power factor (cos 0)
  • Stator resistance per phase (R1)
  • Blocked rotor current and the power factor.

The procedure for drawing the circle diagram of the induction motor is given as follows −

Step 1 − Take the stator voltage phasor (V1) along the y-axis.

Step 2 − Choose a convenient scale for the current. With origin O, draw a line segment OO' = I0 at an angle 0 with voltage phasor V1.

Step 3 − Draw a line OQN perpendicular to voltage (V1). Also, draw a line O'D perpendicular to voltage V1.

Step 4 − From origin O draw a line of length equal to the blocked rotor current (I1BR) to the same scale as that of I0. This line lags behind the voltage phasor V1 by an angle equal to the blocked rotor power factor angle (&varphi_{1BR}).

Step 5 − Join O'A and measure its magnitude in amperes. The magnitude of the line O'A is the value of current (I'2BR).

Step 6 − From the point A, draw a line AMN which is parallel to voltage phasor V1. This line is perpendicular to O'D and ON.

Step 7 − Calculate the value of MP as,

$$\mathrm{MP \:= \: \frac{I'^{2}_{2BR}R_{1}}{V_1}}$$

And locate point P. Then, join O'P and extend it to meet the circle at point B. It is to be noted that slip s is infinity at the point B.

Step 8 − Now, draw the perpendicular bisector of the chord O'A. This bisector will pass through the centre of the circle C. Therefore, with radius CD' or CD, draw the circle, which is the circle diagram of the induction motor (see Figure-5).

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